RT，我的快读一直返回 interger constant is too large for its type.

这是我的快读。

inline ll read(void)
{
	ll w=0; char ch=getchar();
	while(!isdigit(ch)) ch=getchar();
	for(;isdigit(ch);ch=getchar()) w=(w<<1)+(w<<3)+(ch^48);
	return w;
}