嘤嘤嘤，如题目所示。

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
	int k,n,a=0,b=0,age=0,bge=0,f1;
	double c,d;
	cin>>k>>n;
	for(f1=1;f1<=n;f1++)
	{
		if(f1%k==0)
		{
		age+=f1;
		a++;
		}
		else
		 {
		 	bge+=f1;
		 	b++;
		 }
		

}
	c=double (age)/double (a);
	d=double (bge)/double (b);
	c*=1.00;
	d*=1.00;
	printf("%.1f",c);
	printf("%.1f",d);
	return 0;
}