a1a_1a1 % b=c1b = c_1b=c1
a2a_2a2 % b=c2b = c_2b=c2
且 c1+c2=bc_1 + c_2 = bc1+c2=b
那么 (a1+a2)(a_1 + a_2)(a1+a2) % b=0b = 0b=0 是否成立?