#include <stdio.h>

int main(){
	int n;
	scanf("%d", &n);
	int m;
	scanf("%d", &m);
	int k, x = 1;
	for(k = 0; k<n-1; k++){
		x = x * 10;
	}
	
	//对数字串每位数字的提取方法如下：
	int a[n]; 
	for(k = 0; k<n; k++){
		int S = m / x;
		a[k] = S % 10;
		x = x / 10;
	}
	
	//用数表构建显示屏，1代表"X"，0代表"." 
	int b[5] [1005]; 
	int i;
	for(k = 0; k < 5; k++){
		for(i = 0; i < (4*n-1); i++){
			b[k][i] = 0;
		}
	}
	
	for(k = 0; k < n; k++){
		switch(a[k]){
			case 0:
				for(i=0; i<5; i++){
					b[i][4*k] = 1;
					b[i][4*k+2] = 1;
					
				} 
				b[0][4*k+1] = 1;
				b[4][4*k+1] = 1;
				break;
			case 1:
				for(i = 0; i < 5; i++){
					b[i][4*k+2] = 1;
				}
				break;
			case 2:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k+2] = 1;
				b[3][4*k] = 1;
				break;
			case 3:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k+2] = 1;
				b[3][4*k+2] = 1;
				break;
			case 4:
				for(i = 0; i < 3; i++){
					b[i][4*k] = 1;
				}
				for(i = 0; i < 5; i++){
					b[i][4*k+2] = 1;
				}
				b[2][4*k+1] = 1;
				break;//每段case分支别忘加break 
			case 5:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k] = 1;
				b[3][4*k+2] = 1;
				break;
			case 6:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k] = 1;
				b[3][4*k+2] = 1;
				b[3][4*k] = 1;
				break;
			case 7:
				for(i = 0; i < 5; i++){
					b[i][4*k+2] = 1;
				}
				b[0][4*k] = 1;
				b[0][4*k+1] = 1;
				break;	
			case 8:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k] = 1;
				b[3][4*k+2] = 1;
				b[3][4*k] = 1;
				b[1][4*k+2] = 1;
				break;
			default:
				for(i = 4*k; i < (4*k +3); i++){
					b[0][i] = 1;
					b[2][i] = 1;
					b[4][i] = 1;
				}
				b[1][4*k] = 1;
				b[3][4*k+2] = 1;
				b[1][4*k+2] = 1;
		} 
	}
	
	//输出结果 
	for(k = 0; k < 5; k++){
		for(i = 0; i < (4*n-1); i++){
			if(b[k][i]){
				printf("X");
			} else{
				printf(".");
			}
		}
		printf("\n");
	}
	
	return 0;
}