P1002题解
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P1002题解
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Haze_Unpredictable楼主2025/2/4 09:48

P1002(不发1001,太简单了)

#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#define ll long long
using namespace std;
const int fx[] = {0, -2, -1, 1, 2, 2, 1, -1, -2};
const int fy[] = {0, 1, 2, 2, 1, -1, -2, -2, -1};
int bx, by, mx, my;
ll f[40][40];
bool s[40][40]; 
int main(){
    scanf("%d%d%d%d", &bx, &by, &mx, &my);
    bx += 2; by += 2; mx += 2; my += 2;
    f[2][1] = 1;
    s[mx][my] = 1;
    for(int i = 1; i <= 8; i++) s[mx + fx[i]][my + fy[i]] = 1;
    for(int i = 2; i <= bx; i++){
        for(int j = 2; j <= by; j++){
            if(s[i][j]) continue;
            f[i][j] = f[i - 1][j] + f[i][j - 1];
        }
    }
    printf("%lld\n", f[bx][by]);
    return 0;
}
2025/2/4 09:48
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