5分求调
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5分求调
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tcdl85楼主2024/12/16 17:28
#include<iostream>
using namespace std;
long long a[100005] = {0};
int main(){
	long long t , n , i,mx = 0 , f = 0;
	cin >> t;
	while(t--)
	{
		cin >> n;
		for(i = 0 ; i<n ; i++)
		{
			cin >> a[i];
			if(a[i] > mx)
				mx = a[i];
		}
		f = 0;
		for(i = 0 ; i<n ; i++)
		{
			if(mx%a[i] != 0)
			{
				f=1;
				break;
			}
		}
		if( f == 0 ) cout << "Yes" << endl;
		else cout << "No" << endl;
	}
	
 	return  0;	
} 

2024/12/16 17:28
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