#include<iostream>
using namespace std;
int n,a[1000001]={0,1,2,3,3,4,4,4,4,5,5};
int ans=0;
int main()
{
cin>>n;
for(int i=11;i<=n;i++)
{
if(i%2)
{
a[i]=a[i/2+1]+1;
}
else
{
a[i]=a[i/2]+1;
}
}
for(int i=1;i<=n;i++)
{
ans+=a[i]%998244353;
}
cout<<ans % 998244353<<endl;
return 0;
}
O(n)的算法过不了啊QWQ