数据 AC 样例 TLE 求助
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数据 AC 样例 TLE 求助
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紊莫turtle楼主2024/12/12 08:23

https://www.luogu.com.cn/record/194028549

#include <bits/stdc++.h>
#define int long long

#define F(i, a, b) for (int i = (a); i <= (b); i++)
#define dF(i, a, b) for (int i = (a); i >= (b); i--)
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;

mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());
int qpow(int a, int b, int mod) {
    int res = 1;
    for (; b; b >>= 1, a = a * a % mod)
        if (b & 1) res = res * a % mod;
    return res;
}
int i2, P;
struct num {
    int x, y;
    friend num operator * (num a, num b) {
        return (num){(a.x * b.x % P + a.y * b.y % P * i2 % P) % P, 
                     (a.x * b.y % P + a.y * b.x % P) % P};
    }
};
int Cipolla(int n, int p) {
    int a = rnd() % p, b = p - 1 >> 1;
    if (qpow(n, b, p) == p - 1) return -1;
    while (!a || qpow((a * a % p - n + p) % p, b, p) == 1)
        a = rnd() % p;
    i2 = (a * a - n + p) % p, P = p; 
    num x, y;
    x = {1, 0}, y = {a, 1}, b = p + 1 >> 1;
    for (; b; b >>= 1, y = y * y)
        if (b & 1) x = x * y;
    return x.x;
}
void solve(int TC) {
    int n, p, ans1, ans2;
    cin >> n >> p;
    ans1 = Cipolla(n, p);
    if (ans1 == -1) {
        cout << "Hola!\n";
        return;
    }
    ans2 = (p - ans1) % p;
    if (ans1 > ans2) swap(ans1, ans2);
    if (ans1 == ans2) cout << ans1 << '\n';
    else cout << ans1 << ' ' << ans2 << '\n';
}
signed main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);
    int T;
    cin >> T;
    for (int i = 1; i <= T; i ++) {
        solve(i);
    }
    return 0;
}

Cipolla 的随机部分跑不出来了?

2024/12/12 08:23
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