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1260108
yangshihuanhhh楼主2024/12/6 23:06

代码如下

#include<bits/stdc++.h>
using namespace std;

int main() {
    int x,y,z,n,m;
    long long ans=0;
    cin>>x>>y>>z>>n>>m;
    for(int gji=0;gji<=n/x;gji++){
        for(int mji=0;mji<=m/y;mji++){
            int xiaoji=m-gji-mji;
            if(gji+mji+xiaoji==m && gji*x+mji*y+xiaoji/z==n && xiaoji%z==0){
                ans++;
            }
        }
    }
    cout<<ans;
    return 0;
}

2024/12/6 23:06
加载中...