a4−16⋅a3+80⋅a2−128⋅a+100a2−8⋅a+16\frac{a^4-16\cdot a^3 +80\cdot a^2-128\cdot a+100}{a^2-8\cdot a +16}a2−8⋅a+16a4−16⋅a3+80⋅a2−128⋅a+100的最小值是什么
