rt
#include<bits/stdc++.h>
using namespace std;
const int N = 1e5+5;
int t[N*4], a[N], alazy[N*4], mlazy[N*4]; // 加懒标记 和 乘懒标记
int n, q, p; // 数列大小,操作次数,取模数
void push_up(int id)
{
t[id] = t[id << 1] + t[id << 1 | 1] % p;
}
void build(int id, int l, int r)
{
alazy[id] = 0, mlazy[id] = 1;
if(l == r)
{
t[id] = a[l] % p;
return ;
}
int mid = l + r >> 1;
build(id << 1, l , mid);
build(id << 1 | 1, mid + 1 , r);
push_up(id);
}
void apushdown(int id, int l, int r, int mid)//加懒标记下放操作
{
//左子节点
t[id<<1] = (t[id<<1] + (mid - l + 1) * alazy[id]) % p;
alazy[id<<1] = (alazy[id<<1]+alazy[id]) % p;
t[id<<1|1] = (t[id<<1|1] + (r - mid) * alazy[id]) % p;
alazy[id<<1|1] = (alazy[id<<1|1] + alazy[id]) % p;
alazy[id] = 0;
}
void mpushdown(int id, int l, int r, int mid)
{
t[id<<1] = (t[id<<1] * mlazy[id]) % p;
mlazy[id<<1] = (mlazy[id<<1] * mlazy[id]) % p;
alazy[id<<1] = (alazy[id<<1] * mlazy[id]) % p; //记得同时维护加懒标记
t[id<<1|1] = (t[id<<1|1] * mlazy[id]) % p;
mlazy[id<<1|1] = (mlazy[id<<1|1] * mlazy[id]) % p;
alazy[id<<1|1] = (alazy[id<<1|1] * mlazy[id]) % p;
mlazy[id] = 1;//乘法重置为1
}
void pushdown(int id, int l, int r, int mid)
{
//先乘后加
mpushdown(id, l, r, mid);
apushdown(id, l, r, mid);
}
int query(int id, int l, int r, int x, int y)//询问
{
if(x <= l && y >= r) return t[id];//若询问区间内包含结果
int mid = l + r >> 1, res = 0;
pushdown(id, l, r, mid);
if(x <= mid) res =(res + query(id<<1|1,l,mid,x,y)) % p; // 包含左子区间
if(y > mid) res = res + query(id<<1|1,mid+1,r,x,y) % p; // 包含右子区间
return res % p; // 返回
}
void add(int id, int l, int r, int x, int y, int v)//加法运算
{
if(x <= l && y >= r)
{
t[id] = (t[id] + (r - l + 1) * v) % p;//父节点赋值,每个子节点的v都加一遍
alazy[id] = (alazy[id] + v) % p; //懒标记更新
return ;
}
int mid = l + r >> 1;
pushdown(id, l, r, mid);
if(x <= mid) add(id<<1, l, mid, x, y, v);
if(y > mid) add(id<<1|1, mid + 1, r, x, y, v);
push_up(id);
}
void mul(int id, int l, int r, int x, int y, int v)//乘法运算
{
if(x <= l && y >= r)
{
t[id] = (t[id] * v) % p;//父节点赋值,每个子节点的v都加一遍
alazy[id] = (alazy[id] * v) % p; //懒标记更新
mlazy[id] = (mlazy[id] * v) % p;
return ;
}
int mid = l + r >> 1;
pushdown(id, l, r, mid);
if(x <= mid) mul(id<<1, l, mid, x, y, v);
if(y > mid) mul(id<<1|1, mid + 1, r, x, y, v);
push_up(id);
}
int main()
{
cin >> n >> q >> p;
for(int i = 1; i <= n; i++)
{
cin >> a[i];
}
build(1, 1, n);
while(q--)
{
int op, x, y, k;
cin >> op >> x >> y;
if (op == 1)
{
cin >> k;
mul(1, 1, n, x, y, k);
}
else if(op == 2)
{
cin >> k;
add(1, 1, n, x, y, k);
}
else
{
int ans = query(1, 1, n, x, y);
cout << ans << endl;
}
}
return 0;
}