for(int i = 1, x, y; i <= m; i ++) {
        Miku(x, y);
        if(q[x] && q[x] != y) return cout << "0\n", void();
        if(q[x]) continue;
        q[x] = y; s[++ k] = {x, y};
    }

没输入完直接 return 可以过掉全部的样例，汗流浃背了