C 90分 求助
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C 90分 求助
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snoop_ted楼主2024/11/24 22:42
#include<stdio.h>
int main()
{
    int a[12], have = 300, save = 0;
    for (int i = 0; i < 12; i++)
    {
        scanf("%d", &a[i]);
    }
    for (int i = 0; i < 12; i++)
    {
        if (have < a[i])
        {
            printf("-%d", i+1 ); 
            return 0;
        }
        have = have - a[i];
        if (have >= 100)
        {
            save += have / 100;
            have %= 100;
        }
        have += 300;
    }
    have = save * 1.2 * 100 + have - 300;
    printf("%d", have);
    return 0;
}

yw

2024/11/24 22:42
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